Jump to content

  • Quick Navigation
Photo
- - - - -

Help with protein increase formula


  • You cannot start a new topic
  • Please log in to reply
2 replies to this topic

#1 J Young

J Young

    Grade - Active

  • IFSQN Associate
  • 16 posts
  • 1 thanks
0
Neutral

  • United Kingdom
    United Kingdom

Posted 29 October 2014 - 10:19 AM

HI All - brain dead this morning and would like some help producing a formula

 

have product which has 8.5% protein content, ie 8.5%

would like to raise this to 16%

have protein powder available which has 50% protein per gram.

 

Can anybody help as my workings just don't look right!!

I'm sure its starring me in the face - dammed maths!

 

many thanks.



#2 RG3

RG3

    Grade - PIFSQN

  • IFSQN Principal
  • 501 posts
  • 164 thanks
74
Excellent

  • United States
    United States
  • Gender:Male
  • Interests:"We cannot solve our problems with the same thinking we used when we created them" Albert Einstein

Posted 29 October 2014 - 03:33 PM

What are the total grams used in your batch?



#3 Ratchet

Ratchet

    Grade - Active

  • IFSQN Associate
  • 19 posts
  • 8 thanks
0
Neutral

  • United States
    United States
  • Gender:Male
  • Location:SC

Posted 07 November 2014 - 03:40 PM

I had a diagram here but the copy and paste didn't work to well. Subtract 16 from 50, and 8.5 from 16. This gives you a ratio of 7.5 parts of 50% added to 34 parts of 8.5% to give you 41.5 parts at 16%. This is a Pearson Square that I used often -( http://www.ext.colos...tk/01618.html.)It is easy to change to % for the mix. Just divide total parts (41.5) into 100 to give you a multiplier of 2.41, use this against the parts needed of both,(34 and 7.5} and that should end up to 100 parts or 100%.
Hope you can follow this. Try the website, it is much clearer than my humble try before I remembered the name of the method.

Try this instead -   http://msucares.com/...ions/p2632.html


Edited by ratcht, 07 November 2014 - 04:00 PM.





0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users