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Translate the logarithm value of bacteria into number of bacteria?


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#1 Indican3

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Posted 15 July 2016 - 05:04 PM

Hi All

Just want to understand how to translate the logarithm value of bacteria into number of bacteria. So, for example if we have staphylococcus at 8.09log10, what would be the translation into number of bacteria/g or cfu/g.

 

Thanks for the help!!



#2 Charles.C

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Posted 15 July 2016 - 09:36 PM

Hi All

Just want to understand how to translate the logarithm value of bacteria into number of bacteria. So, for example if we have staphylococcus at 8.09log10, what would be the translation into number of bacteria/g or cfu/g.

 

Thanks for the help!!

 

Hi Divy

 

I guess that the "10" in yr post was supposed to be in subscript, ie number was 8.09log10

 

For a relatively non-technical explanation of logarithms see 1st link in this post -

 

http://www.ifsqn.com...rts/#entry91004

 

For a direct calculation see the link/example in this post (your "8.09" will replace the  "2.5") -

 

http://www.ifsqn.com...on/#entry100637

(answer should be 123,026,877.0812 cfu/gram assuming that cfu/gram was the original unit used)

 

NOTE - if yr original number was actually 8.09log10(10) the answer will be (a lot) different.


Kind Regards,

 

Charles.C





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